Just proves, never too late to learn :-)
I would have got 1 by doing 2(2+2) = 8 first. Not because of bracket but because of “implied multiplication.”
Yeah, right answer but wrong reason. There’s no such thing as implicit multiplication.
What I am learning here: 8÷2(2+2) is not same as 8÷2×(2+2)
Correct, and that’s because of Terms - 8÷2(2+2) is 2 terms, with the (2+2) in the denominator, but 8÷2×(2+2) is 3 terms, with the (2+2) in the numerator… hence why people get the wrong answer when they add an extra multiply in.
number next bracket is not the same as normal multiplication in rule book
Right, because it’s not “multiplication” at all (only applies literally to multiplication signs), it’s a coefficient of a bracketed term, which means we have to apply The Distributive Law as part of solving Brackets.
÷ & × have right of way rule with whoever is left most wins
Yeah, the actual rule is Left associativity, and going left to right is the easy way to obey that.
multiple always happens first. But apparently it’s what’s left side first
Multiplication and division are equal precedence (and done left to right) if that’s what you’re talking about, but the issue is that a(b+c) isn’t “multiplication” at all, it’s a bracketed term with a coefficient which is therefore subject to The Distributive Law, and is solved as part of solving Brackets, which is always first. Multiplication refers literally to multiplication signs, of which there are none in the original question. A Term is a product, which is the result of a multiplication, not something which is to be multiplied.
If a=2 and b=3, then…
axb=2x3 - 2 terms
ab=6 - 1 term
P.S. feel free to read through and use my thread on order of operations.
inside radicals
I had to look up what that meant (should’ve done that the first time - sorry) - have never heard that before, must be a local terminology.
So, square roots (or other roots) can be expressed as an exponent - e.g. the square root of 2 is the same as 2 to the power ½ - so that’s covered by “E”, exponents! (or I for Index, or O for to the Order of, depending on your area)
I appreciate your mention of the importance of teaching the difference between operators and terms
Thank you.
My pedagogical background is in the sciences and I’m much better at doing math than teaching it
Oh god, welcome to why I have so many people argue with me, a Maths teacher, about it. There’s a whole bunch of Youtubes and blogs out there by Physics majors. I’m like “OMG, why are you trusting someone with a Physics major over someone with a Maths major - god help me”.
I would like if math classes (in my area) did more explicitly teach the difference between terms and operators
So what area are you in? A country will do. You said PEMDAS so I’m guessing the U.S.? I’ve heard via Youtubes/blogs that indeed there is more confusion with what is taught there, but I ended up Googling for U.S. textbooks, and found the same thing being taught in the textbook, so I’m not sure where this “that’s not what they teach in the U.S.” is coming from (why I was Googling for U.S. textbooks in the first place). Is the standard of teachers there actually worse than elsewhere? Or is it perhaps (possibly more likely) that there’s just more U.S. people posting, therefore more people who’ve forgotten the actual rules, and are just (as I’ve seen many times) they’re just blaming it on what they were taught (which I’ve usually found isn’t true at all).
Ok, that’s a start. In your simple example they are all equal, but they aren’t all the same.
yn+y - 2 terms
y(n+1) - 1 term
y×(n +1) - 2 terms
To see the difference, now precede it with a division, like in the original question…
1÷yn+y=(1/yn)+y
1÷y(n+1)=1/(yn+y)
1÷y×(n +1)=(n +1)/y
Note that in the last one, compared to the second one, the (n+1) is now in the numerator instead of in the denominator. Welcome to why having the (2+2) in the numerator gives the wrong answer.
The y(n+1) is same as yn + y
No, it’s the same as (yn+y). You can’t remove brackets unless there is only 1 term left inside.
if you removed the “6÷” part. It’s
…The Distributive Law.
It doesn’t make sense in BODMAS either. Expanding Brackets has precedence of… Brackets, not “multiplication” - “Multiplication” refers literally to multiplication signs, of which there are none in this question.
I’ve taught a class of kids that has various disabilities. Having a disability doesn’t make you stupid.
But then you would have to define what a “Group” is as well, adding yet another definition needing to be remembered. Terms are actually defined, and cover the first 2 steps, and then the rest are operators (binary then unary).
Well thanks to you too for a proper conversation. :-) There’s a lot of people here wanting to pull out their pitchforks over the smallest thing.
e.g. you made a comment about teaching the “scientific” method to kids, and I can tell you as a teacher that we already do (but the OP never looked at any Maths textbooks, nor asked any Maths teachers) :-)
Yeah, I thought maybe you meant that, but I wasn’t sure, and in any case I wanted to make clear it’s totally worthless to use as a source for anything else (for the reasons I mentioned). :-)
That’s cool. I’m not sure what you mean about not using it as a source though, because that was also my point! If you want sources for how this should actually be done (and what actually is taught at school), then see my thread - contains actual textbook references (where there’s a screenshot of a textbook, the place it’s come from is in the top-left of the screenshot), actual historical documents (Lennes and Cajori), worked examples, proofs, etc. You said you believe in “strong juxtaposition”, so we’re kinda in agreement - I’m just pointing out that the actual rules are Terms and The Distributive Law (i.e. 2 different rules have been lumped together as one under the “strong juxtaposition” banner), neither of which is discussed anywhere in the blog (and when I, and others, have pointed this out, the OP has ignored us and downvoted our comments). I also made 5 fact check posts rebutting the false/misleading claims made in the blog - just sort the comments here by “new” and you’ll see them (no prizes for guessing who downvoted them).
In other words, I wasn’t saying “don’t pay attention to any blog posts” (which I think is what you thought I meant?), I was saying “don’t pay attention to this blog post” (for multiple reasons that I’ve posted in many places in here).
Not sure how you came up with that conclusion. I never said anything about it being “just a blog post”.
You said…
I don’t understand how the author of the post lands on “there is no good or bad way, they are all valid”
And I’m pointing out he arrived at that by ignoring what’s taught in high school, which is where it’s taught (not in academia). It’s like saying “It’s ambiguous if there’s such a thing as rain” if you present weather evidence which has omitted every single rainy day that has happened. i.e. cherry-picking. Every single blog which says it’s ambiguous has done the exact same thing. You can find what actually is taught in high school here
Check a high school Maths textbook - even easier!
It’s what is actually taught in high school, so there are those who remember and those who don’t.
You are correct with your definition - Terms are separated by operators and joined by grouping symbols - and it’s consequently not ambiguous at all (using so-called “weak juxtaposition” breaks that rule).
enforce writing math without ambiguity
It already is written without ambiguity.
were taught in third grade
This is actually taught in Year 7 - the people who only remember the 3rd Grade version of the rules are the ones getting it wrong.
You’re welcome.